input_string = "01-result.xls,2-result.xls,03-result.xls,05-result.xls"
# Must be turned into ['result1','result2', 'result3', 'result5']
splitted = input_string.split(',')
newsplitted = ["".join(x.split('.')[0].split('-')[::-1]) for x in splitted ]
这是我到目前为止尝试过的：
final = []
for Y in newsplitted :
final =[Y.replace('0','')]
只是为了学习,如果我想在另一个for循环的最后做替换部分,那该怎么做？
input_string = "01-result.xls,2-result.xls,03-result.xls,05-result.xls"
result = [''.join(i.split('-')[::-1]).replace('.xls', '').replace('0', '') for i in input_string.split(',')]
结果
['result1', 'result2', 'result3', 'result5']
这基本上与
result = []
for i in input_string.split(','):
formatted_element = ''.join(i.split('-')[::-1]).replace('.xls', '').replace('0', '')
result.append(formatted_element)
在您的情况下,您应该这样做：
[Y.replace('0', '') for Y in newsplitted]
要么
final = []
for Y in newsplitted :
final.append(Y.replace('0',''))
我建议您阅读有关python中列表推导的更多信息
http://treyhunner.com/2015/12/python-list-comprehensions-now-in-color/
您可以随时参考文档
https://docs.python.org/3.5/tutorial/datastructures.html#list-comprehensions